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A hydrogen atom in a state having a bind...

A hydrogen atom in a state having a binding energy of 0.85 eV makes transition to a state with excitation energy 10.2 eV. The quantum number n of the upper and the lower energy states are

A

1,3

B

2,4

C

1,4

D

3,4

Text Solution

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The correct Answer is:
B
`(13.6)/(n^(2))=0.85 implies n=4`
`10.2=13.6((1)/(1^(2))-(1)/('^(2))) implies n'=2`
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CP SINGH-BOHR THEORY-Exercises
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  2. A hydrogen sample is prepared in a particular state A photon of energy...

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  3. A hydrogen atom in a state having a binding energy of 0.85 eV makes tr...

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  4. Imagine an atom made of a proton and a hypothetical particle of double...

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  5. In an excited state of hydrogen like atom an electron has total energy...

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  6. Light form a dicharge tube containing hydrogen atoms falls on the surf...

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  7. The electron in the hydrogen atom jumps from excited state (n=3) to it...

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  8. Three photons coming from excited atoms hydrogen sample are picked up ...

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  9. In a laboratory experiment on emission from atomic hydrogen in a disch...

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  10. The de-Broglie wavelength of an electron in the first Bohr orbit is

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  11. Consider an eelctron in the nth orbit of a hydrogen atom in the Bohr m...

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  12. The ratio of the longest and shortest wavelengths of the Lyman series ...

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  13. The ratio of longest wavelength and the shortest wavelength observed i...

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  14. In terms of Rydberg's constant R, the wave number of the first Balman ...

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  15. The wavelength of the first line of the Balmer series of hydrogen atom...

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  16. The wavelength of the first line of Lyman series for hydrogen atom is ...

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  17. Every series of hydrogen spectrum has an upper and lower limit in wave...

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  18. Let v(1) be the frequency of series limit of Lyman series, v(2) the fr...

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  19. The transtion from the state n = 4 to n = 3 in a hydrogen like atom r...

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  20. Whenever a hydrogen atom emits a photon in the Balmer series, it may...

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