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The de-Broglie wavelength of an electron...

The de-Broglie wavelength of an electron in the first Bohr orbit is

A

equal to one fourth circumference of the first orbit

B

equal to half the circumference of the first orbit

C

equal to twice the circumference of the first orbit

D

equal to the circumference of the first orbit

Text Solution

Verified by Experts

The correct Answer is:
D
`2pir_(n)=n lamda`
`n=1, lamda=2 pi r_(1)`
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