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The radius of the hydrogen atom in its g...

The radius of the hydrogen atom in its ground state is `5.3xx10^(-11)` m. The principal quantum number of the final state of the atom is

A

2

B

3

C

4

D

16

Text Solution

Verified by Experts

The correct Answer is:
A
`r_(n) prop n^(2)`
`(r_(2))/(r_(1))=((n_(2))/(n_(1)))^(2) implies (21.2xx10^(-11))/(5.3xx10^(-11))=((n_(2))/(n_(1)))^(2)`
`(n_(2))/(n_(1))=2 implies (n_(2))/(1)=2`
`n_(2)=2`
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