" Q) Find distence of pomt "(1,-2,3)" trom plone "x-y+z=5

Find the equation of the plane through the point (1,2,3) and perpendicular to the plane x-y+z=2 and 2x+y-3z=5

If Q is the image of the point P (2,3,4) under the reflection in the plane x-2y+5z=6 then the equation of the line PQ is a) (x-2)/(-1)= (y-3)/2= (z-4)/5 b) (x-2)/(1)= (y-3)/(-2)= (z-4)/5 c) (x-2)/(-1)= (y-3)/(-2)= (z-4)/5 d) (x-2)/(1)= (y-3)/(2)= (z-4)/5

Find the acute angle between the planes 2x-3y+5z=1 and x-y-z=7 .

Find the value of 'p' if the lines (x-5)/7=(y+2)/(-5)=z/1 and x/1=y/p=z/3 are perpendicular .

Find the image of the line (x-1)/3=(y-2)/4=(z-3)/5 on the plane x-2y+z+2=0 .

Find the angle betweenthe line (x-2)/-1=(y+3)/2=(z+4)/3 and the plane 2x-3y+z=5 .

If A=[(2,-3,5),(3,2,-4),(1,1,-2)] , find A^(-1) and hence solve the system of linear equations: \ 2x-3y+5z=11 ,\ \ 3x+2y-4z=5,\ \ x+y-2z=-3

Find the distance between the points P(x_(1),y_(1),z_(1)) and Q(x_(2),y_(2),z_(2))

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1) (x+3)/3=(y-5)/1=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/5 (3) (x-3)/3=(y+5)/1=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/5