The dissociation constant of n-butyric acid is `1.6 xx 10^(-5)` and the molar conductivity at infinite dilution is `380 xx 10^(-4) Sm^(2) mol^(-1)`. The specific conductance of the `0.01M` acid solution is

Options

A. `1.52 xx 10^(-5) S`
B. `1.52 S`
C. `1.52 xx 10^(-3) S`
D. `1.52 xx10^(-4) S`

Answer

B

Explanation

`alpha = sqrt(K_(alpha))/(C ) = sqrt(1.6 xx10^(-5))/(0.01)`
`lambda_(m) = alphal lambda_(m)^(@) = (K xx 1000)/("molarity")` when `lambda_(m)` is in `S cm^(2)mol^(-1)`
`G = (K)/("cell constant")`