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CdO has NaCl like structure with density...

`CdO` has `NaCl` like structure with density `8.27g//c c`. If the ionic radius of `O^(2-)` is `1.24A^(@)` determine the ionic radius of `Cd^(2+)`:

A

`1.5 A^(@)`

B

`1.1 A^(@)`

C

`1.9 A^(@)`

D

`1.5 A^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
`rho = (Z xx M)/(N_(A) xx alpha^(3)) rArr alpha = (r_(Cd^(2)) + r_(O^(2-)))`
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