Considering no electronic repulsion in Helium atom what will be Bohr's energy for both the electrons ? Bohr's energy of ground state of `H-` atom is `- 13.6 eV`

Options

A. `- 13.6 eV`
B. `- 27.2 eV`
C. `- 108.8 eV`
D. `- 54.4 eV`

Answer

C

Explanation

If no electronic repulsion is there than He can be treated as two mono electronic atoms so
`E_(He) = -13.6 xx (z^(2))/(n^(2)) rArr 13.6 xx 4 = - 54.4 eV`
For both electronic system `rArr -54.4 xx 2 = -108.8 eV`.