Calculate work done during isothermal reversible process when `5 mol` ideal gas is expanded so that its volume is doubled at `400K`.

Options

A. `-11.5 kJ`
B. `- 344 kJ`
C. 0
D. `-2.8 kJ`

Answer

A

Explanation

`W_("isoreversible") = -2.303nRT "log" (V_(2))/(V_(1))`
`= -2.303 xx 5 xx 8.314 xx 400 xx log2`
`= -2.303 xx 5 xx 8.314 xx 400 xx 0.3J`
`= -11488.28J`