The `K_(sp)` of `AgCl` at `25^(@)C` is `2.56 xx 10^(-10)`. Then how much volume of `H_(2)O` is required to dissolve `0.01` mole of salt ?

Options

A. `800 L`
B. `400 L`
C. `625 L`
D. `50 L`

Answer

C

Explanation

`AGCl hArr Ag^(+) underset(s)((aq)) + Cl^(-) underset(s)((aq))`
`K_(sp) = S^(2) = 2.56 xx 10^(-10) = 256 xx 10^(-12)`
`S = 16 xx 10^(-6) = 1.6 xx 10^(-5) mol//L`
`1.6 xx 10^(-5) = (0.01)/(Vol(L))`
`V = (0.01)/(1.6 xx 10^(-5)) = 625L`