For a first order reactin, rate constant is given is `log k = 14 - (1.2 xx 10^(4))/(T)`, then what will be value of temperature if its half life period is `6.93 xx 10^(-3) min` ?

Options

A. `100 K`
B. `1000 K`
C. `720 K`
D. `327 K`

Answer

B

Explanation

`logk = 14 - (1.2 xx 10^(4))/(T)` …….(i)
`logk = log A - (E_(a) )/(2.303RT)`
`t_(1//2) = 6.93 xx 10^(-3) min`
`k = (0.693)/(6.93 xx 10^(-3)) = 100`
`log 100 = 14 - (1.2 xx 10^(4))/(T)`
`rArr T = 1000K`