`50 ml` of `1 M`, oxalic acid is shaked with `0.6 gm` of charcoal. The final concentration of this solution after adsorption has been found to be `0.4 M`. The amount of oxalic acid absorbed per `gm` of charcoal is

Options

A. `2.02 gm`
B. `2.52 gm`
C. `3.02 gm`
D. `3.52 gm`

Answer

B

Explanation

Moles of oxalic acid `= (50 xx1)/(1000) = (1)/(20)`
Weight of oxalic acid `= (1)/(20) xx 126 = 6.3 gm`
Conc. Of solution after adsorption `= 0.4 M`
Moles of oxalic acid after adsorption `= (50 xx 0.4)/(1000) = (1)/(50)`
Wt. of oxalic acid after adsorption `= (1)/(50) xx 126 = 2.52 gm`