Following are three equations of motion `S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at` Where `,S,u,t,a,v` are respectively the displacement `(` dependent variable `)`, initial `(` constant `)`, time taken `(` independent variable `)`, acceleration `(` constant `)` and final velocity `(` dependent variable `)` of the particel after time `t`. Find the displacement of a particle after 10 seconds starting from rest with a uniform acceleration of `2m//s^(2)`
Following are three equations of motion S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at Where ,S,u,t,a,v are respectively the displacement ( dependent variable ) , initial ( constant ) , time taken ( independent variable ) , acceleration ( constant ) and final velocity ( dependent variable ) of the particel after time t . Find the velocity of the particle after 10 seconds if its acceleration is zero in interval (0 to 10s)-
Following are three equations of motion S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at Where ,S,u,t,a,v are respectively the displacement ( dependent variable ) , initial ( constant ) , time taken ( independent variable ) , acceleration ( constant ) and final velocity ( dependent variable ) of the particel after time t . Find the displacement of the particle when its velocity becomes 10m//s if acceleration is 5m//s^(2) all through -
A particle having initial velocity u moves with a constant acceleration a for a time t. a. Find the displacement of the particle in the last 1 second . b. Evaluate it for u=5m//s, a=2m//s^2 and t=10s .
Velocity of a particle at any time t is v=(2 hati+2t hatj) m//s. Find acceleration and displacement of particle at t=1s. Can we apply v=u+at or not?
If a man has a velocity varying with time given as v=3t^(2),v is in m//s and t in sec then : Find out his displacement after 2 seconds of his start :
If acceleration of a particle at any time is given by a = 2t + 5 Calculate the velocity after 5 s, if it starts from rest
Starting from rest, the acceleration of a particle is a=2(t-1) . The velocity (i.e. v=int" a dt " ) of the particle at t=10 s is :-
A particle is moving with velocity v=4t^(3)+3 t^(2)-1 m//s . The displacement of particle in time t=1 s to t=2 s will be
RESONANCE-DAILY PRACTICE PROBLEMS-dpp 92 illustration