Following are three equations of motion `S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at` Where `,S,u,t,a,v` are respectively the displacement `(` dependent variable `)`, initial `(` constant `)`, time taken `(` independent variable `)`, acceleration `(` constant `)` and final velocity `(` dependent variable `)` of the particel after time `t`. Find the velocity of a particle after `100m-`
Following are three equations of motion S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at Where ,S,u,t,a,v are respectively the displacement ( dependent variable ) , initial ( constant ) , time taken ( independent variable ) , acceleration ( constant ) and final velocity ( dependent variable ) of the particel after time t . Find the displacement of a particle after 10 seconds starting from rest with a uniform acceleration of 2m//s^(2)
Following are three equations of motion S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at Where ,S,u,t,a,v are respectively the displacement ( dependent variable ) , initial ( constant ) , time taken ( independent variable ) , acceleration ( constant ) and final velocity ( dependent variable ) of the particel after time t . Find the velocity of the particle after 10 seconds if its acceleration is zero in interval (0 to 10s)-
Following are three equations of motion S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at Where ,S,u,t,a,v are respectively the displacement ( dependent variable ) , initial ( constant ) , time taken ( independent variable ) , acceleration ( constant ) and final velocity ( dependent variable ) of the particel after time t . Find the displacement of the particle when its velocity becomes 10m//s if acceleration is 5m//s^(2) all through -
The initial velocity given to a particle is u and accelration is given by a=at^((3)/(2)) . What will be the velocity of particle after time t.
A particle is moving with initial velocity 1m/s and acceleration a=(4t+3)m/s^(2) . Find velocity of particle at t=2sec .
A particle moves with an initial velocity V_(0) and retardation alpha v , where alpha is a constant and v is the velocity at any time t. Velocity of particle at time is :
If velocity of a particle is given by v=2t^(2)-2 then find the acceleration of particle at t = 2 s.
In the diagram shown, the displacement of particles is given as a function of time. The particle a is moving under constant velocity of 9 m//s . The particle B is moving under variable acceleration. From time t=0 s to t=6 s . The average velocity of the particle B will be equal to :-
For body moving with uniform acceleration a , initial and final velocities in a time interval t are u and v respectively. Then its average velocity in the time interval t is
RESONANCE-DAILY PRACTICE PROBLEMS-dpp 92 illustration
