Find slope of a straight line `2x-5y+7=0`

Explanation

To find the slope of the straight line given by the equation \(2x - 5y + 7 = 0\), we can follow these steps:

### Step 1: Rearrange the equation into slope-intercept form
The slope-intercept form of a line is given by the equation \(y = mx + c\), where \(m\) is the slope and \(c\) is the y-intercept. We need to isolate \(y\) in the given equation.

Starting with the equation:
\[ 2x - 5y + 7 = 0 \]

We can rearrange it to isolate \(y\):
\[ -5y = -2x - 7 \]

### Step 2: Solve for \(y\)
Now, divide every term by \(-5\) to solve for \(y\):
\[ y = \frac{2}{5}x + \frac{7}{5} \]

### Step 3: Identify the slope
From the equation \(y = \frac{2}{5}x + \frac{7}{5}\), we can see that the slope \(m\) is the coefficient of \(x\):
\[ m = \frac{2}{5} \]

### Final Answer
Thus, the slope of the straight line \(2x - 5y + 7 = 0\) is:
\[ \boxed{\frac{2}{5}} \]

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