If a particle starts moving along a straight ine withinitial velocity u under contact acceleration a, its displacement with time is given by the relation `x=ut+(1)/(2)at^2` Q. Differentiation of `x` w.r.t. `t` will be
If a particle starts moving along a straight ine withinitial velocity u under contact acceleration a, its displacement with time is given by the relation x=ut+(1)/(2)at^2 Q. The concerned deviation of positon time realtion w.r.t will be. Differentiation of above result w.r.t. t will be
Differentiation of x^2 w.r.t. x is
Differentiation of sin(x^2) w.r.t. x is
Differentiation of sin(x^(2)+3)w.r.t.x is-
Differentiate cos^(2)x^(3) w.r.t x
Find differentiation of cot x^(2) w.r.t x .
Differentiate sin(x^(2)+5) w.r.t. x.
Differentiate sin(x^(2)+x)w.r.t.x
If a particle starts moving along x-axis from origin with initial velocity u=2m/s and acceleration 4m//s^(2) the relation between displacement and time is given as x=2t+2t^(2) . Draw the displacement time graph for t ul(gt)0 .
Find the differentiation of 2/pisinxo w.r.t. \ x
RESONANCE-DAILY PRACTICE PROBLEMS-dpp 92 illustration