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If y=e^(x).cotx then (dy)/(dx) will be...

If `y=e^(x).cotx` then `(dy)/(dx)` will be

A

`e^(x)cot x-cosec^(2)x`

B

`e^(x) cosec^(2)x`

C

`e^(x)[cot x-cosec^(2)x]`

D

`e^(x)cot x`

Text Solution

Verified by Experts

The correct Answer is:
C

`y=e^(x).cotx`
`(dy)/(dx)=e^(x)(d)/(dx)(cotx)+cotx(d)/(dx)(e^(x))`
`=e^(x)(-cosec^(2)x)+cotxe^(x)`
`=e^(x)[cotx-cosec^(2)x]`
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