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Differentiation of sin(x^(2)+3)w.r.t.x i...

Differentiation of `sin(x^(2)+3)w.r.t.x` is-

A

`cos(x^(2)+3)`

B

`2x cos(x^(2)+3)`

C

`(x^(2)+3) cos(x^(2)+3)`

D

`2x cos(2x+3)`

Text Solution

AI Generated Solution

The correct Answer is:
To differentiate the function \( \sin(x^2 + 3) \) with respect to \( x \), we will apply the chain rule of differentiation. Here’s a step-by-step solution: ### Step 1: Identify the outer and inner functions The function we need to differentiate is \( \sin(f(x)) \) where \( f(x) = x^2 + 3 \). ### Step 2: Apply the chain rule According to the chain rule, the derivative of \( \sin(f(x)) \) is given by: \[ \frac{d}{dx} \sin(f(x)) = \cos(f(x)) \cdot \frac{d}{dx} f(x) \] ### Step 3: Differentiate the inner function Next, we need to differentiate \( f(x) = x^2 + 3 \): \[ \frac{d}{dx} f(x) = \frac{d}{dx} (x^2) + \frac{d}{dx} (3) = 2x + 0 = 2x \] ### Step 4: Substitute back into the chain rule Now, substituting \( f(x) \) and its derivative back into the chain rule: \[ \frac{d}{dx} \sin(x^2 + 3) = \cos(x^2 + 3) \cdot (2x) \] ### Step 5: Write the final answer Thus, the derivative of \( \sin(x^2 + 3) \) with respect to \( x \) is: \[ 2x \cos(x^2 + 3) \] ### Final Answer: \[ \frac{d}{dx} \sin(x^2 + 3) = 2x \cos(x^2 + 3) \] ---

To differentiate the function \( \sin(x^2 + 3) \) with respect to \( x \), we will apply the chain rule of differentiation. Here’s a step-by-step solution: ### Step 1: Identify the outer and inner functions The function we need to differentiate is \( \sin(f(x)) \) where \( f(x) = x^2 + 3 \). ### Step 2: Apply the chain rule According to the chain rule, the derivative of \( \sin(f(x)) \) is given by: \[ ...
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