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y=x(c-x) where c is a constant. Find ma...

`y=x(c-x)` where `c` is a constant. Find maximum value of `y`.

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The correct Answer is:
B, C, D

`(dy)/(dx)=C-2x=0rArrx=(c)/(2)`
`(d^(2)y)/(dx^(2))=-2`
`Y_(max)=(c)/(2)(c-(c)/(2))=(c^(2))/(4)`
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