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Evaluate :- int(0)^(pi//2)(sinx+cosx)d...

Evaluate `:-`
`int_(0)^(pi//2)(sinx+cosx)dx`

Text Solution

Verified by Experts

The correct Answer is:
2

`underset(0)overset(1)int(sinx+cosx)dx=[-cosx]_(0)^(pi//2)+[sinx]_(0)^(pi//2)`
`=1-0+1-0=2`
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