Home
Class 11
PHYSICS
If a=(3t^2+2t+1) m/s^2 is the expression...

If `a=(3t^2+2t+1)` `m/s^2` is the expression according to which the acceleration of a particle varies. Then-
`a=(3t^2+2t+1)` `(m)/(s^2)`
Q. The change in velocity after 3 seconds of its start is:

A

`30m//s`

B

`39m//s`

C

`3m//s`

D

`20m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
`V(t=0)=0`
`V_(t=3)=(3)^(3)+(3)^(2)+3`
`=27+9+3`
`=39`
`DeltaV=39-0=39m//s.`
Promotional Banner

Similar Questions

Explore conceptually related problems

If a=(3t^2+2t+1) m/s^2 is the expression according to which the acceleration of a particle varies. Then- a=(3t^2+2t+1) (m)/(s^2) Q. Find displacement of the particle after 2 seconds of start.

If a=(3t^2+2t+1) m/s^2 is the expression according to which the acceleration of a particle varies. Then- a=(3t^2+2t+1) (m)/(s^2) Q. The expression for instantaneous velocity at any time t will be (if the particle was initially at rest)-

The acceleration a of a particle in m/s^2 is give by a=18t^2+36t+120 . If the particle starts from rest, then velocity at end of 1 s is

Starting from rest, acceleration of a particle is a = 2t (t-1) . The velocity of the particle at t = 5s is

A particle is moving rectilineraly so that its acceleration is given as a = 3t^(2) + 1 m//s^(2) . Its initial velocity is zero.

The angular displacement of a particle is given by theta =t^3 + t^2 + t +1 then, its angular velocity at t=2 sec is …… rad s^(-1)

If the displacement of a particle is givne by s=((1)/(2)t^(2)+4sqrtt)m . Find the velocity and acceleration at t = 4 seconds.

A particle is given an initial velocity of vecu=(3 hati+4 hatj) m//s . Acceleration of the particle is veca=(3t^(2) +2 thatj) m//s^(2) . Find the velocity of particle at t=2s.