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An ant is at a corner of a cubical room ...

An ant is at a corner of a cubical room of side a. The ant can move with a constant speed u. The minimum time taken to reach the farthest corner of the cube is

A

`(3a)/(u)`

B

`(sqrt(3a))/(u)`

C

`(sqrt(5a))/(u)`

D

`((sqrt(2)+1)a)/(u)`

Text Solution

Verified by Experts

The correct Answer is:
C
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on placing back face and bottom face in same plane.

`A rarr` starting point `G rarr ` final point
minimum time `=(sqrt(5)a)/(u)`
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