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A particle moves through the origin of a...

A particle moves through the origin of an `xy-` cordinate system at `t=0` with initial velocity `u=4i-5jm//s`. The particle moves in the `xy` plane with an acceleration `a=2im//s^(2)`. Spped of the particle at `t=4` second is `:`

A

`12m//s`

B

`8sqrt(2)m//s`

C

`5m//s`

D

`13m//s`

Text Solution

Verified by Experts

The correct Answer is:
D
Using `v_(x)=u_(x)+a_(x)t`
`49+(2i)4`
`=121i`
As `a_(y)=0` , velocity component in `y-` direction remains unchanged. Final velocity `=12i-5j` speed at `t=4 sec. =sqrt(12^(2)+(-5)^(2))=13m//s`
`v_(x)=u_(x)=a_(x)t`
`=4i+(2i)4`
`12i`
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