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The velocity of a car moving on a straig...

The velocity of a car moving on a straight road increases linearly accroding to equation, `v=1+bx` , where `a &b` are positive constants. The acceleration in the course of such motion `:(x` is the displacement `)`

A

increases

B

decreases

C

stay constant

D

becomes zero

Text Solution

Verified by Experts

The correct Answer is:
A
`V=a+bx`
`(V` increases as `x` increases `)`
`(dV)/(dx)=b,(dx)/(dt)=V`
so, acceleration `=V(dV)/(dx)=V.b` hence acceleration increases as `V` increases with `x`.
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