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The speed v of a car moving on a straigh...

The speed `v` of a car moving on a straight road changes according to equation, `v^2 = 1 + bx`, where `a and b` are positive constants. Then the magnitude of acceleration in the course of such motion : (x is the distance travelled).

A

increases

B

decreases

C

stay constant

D

becomes zero

Text Solution

Verified by Experts

The correct Answer is:
A
`V=a+bx`
`(V` increases as `x` increases `)`
`(dV)/(dx)=b,(dx)/(dt)=V`
hence acceleration increases as `V` increases with `x`.
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