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If v = x^2 - 5x + 4, find the accelerati...

If `v = x^2 - 5x + 4`, find the acceleration of the particle when velocity of the particle is zero.

A

0

B

2

C

3

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`v=0rArrx^(2)-5x+4=0`
`x=1m& 4m`
`(dv)/(dt)=(2x-5)v=(2x-5)(x^(2)-5x+4)` at `x=1m` and `4m,(dv)/(dt)=0`
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