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A particle is projected from a point (0,...

A particle is projected from a point (0,1) of Y-axis (assume + Y direction vertically upwards) aiming towards a point (4,9). It fell on ground along x axis in 1 sec. Taking `g=10(m)/(s^2)` and all coordinate in metres. Find the X-coordinate where it fell.

A

`93,0)`

B

`(4,0)`

C

`(2,0)`

D

`(2sqrt(5),0)`

Text Solution

Verified by Experts

The correct Answer is:
C

`tan theta=(9-1)/(4-0)=2`
`y=u_(y)t+(1)/(2)a_(y)t^(2)`
now, `-1=u sin theta (1)-(1)/(2)g (1)^(2)`
`usin theta=4 ` and `sin theta=(2)/(sqrt(5))`
`rArr u=2sqrt(5)`
now, `x=ucos theta(1)=(2sqrt(5))xx(1)/(sqrt(5))=2m`
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