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Two smooth block are placed at a smooth ...

Two smooth block are placed at a smooth corner as shown in fig. Both the bloks are having mass m. We apply a force F on the block m. Block A presses block B in the normal direction, due to which pressing force on vertical wall will increase, and pressing force on the horizontal wall decreases, as we increases `F(theta = 37^(@)` with horizontal).

As soon as the pressing force on the horizontal wall by block B become zero, it will lose contact with ground. If the value of F further increases, block B will accelerate in the upward direction and simulaneously block A will towards right.
What is the minimum value of F to lift block B from ground?

A

`(25)/(12)mg`

B

`(5)/(4)mg`

C

`(3)/(4)mg`

D

`(4)/(3)mg`

Text Solution

Verified by Experts

The correct Answer is:
C
For `equli.` of block `(A)`
`F=N sin theta`
`N=F//sin theta`
To lift block `B` from ground
`N cos theta ge mg`
`(F)/(sin theta ) cos theta ge mg`
`Fgemg tan theta=mg((3)/(4))`
So, `F_(mi n)=(3)/(4) mg`
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