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Two smooth block are placed at a smooth ...

Two smooth block are placed at a smooth corner as shown in fig. Both the bloks are having mass m. We apply a force F on the block m. Block A presses block B in the normal direction, due to which pressing force on vertical wall will increase, and pressing force on the horizontal wall decreases, as we increases `F(theta = 37^(@)` with horizontal).

As soon as the pressing force on the horizontal wall by block B become zero, it will lose contact with ground. If the value of F further increases, block B will accelerate in the upward direction and simulaneously block A will towards right.
If both the blocks are stationary, the force exerted by ground of block A is

A

`mg+(3F)/(4)`

B

`mg-(3F)/(4)`

C

`mg+(4F)/(3)`

D

`mg-(4F)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
If both the blocks are stationary,
Balancing forces along `x-` direction
`F=N sin theta rArr N=F//sin theta`

Balancing forces along `y-` direction
`N_(y)=mg+N cos theta`
`=mg+((F)/(sin theta))cos theta=mg+F cot theta`
`N_(y)=mg+(4F)/(3)`
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