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Two smooth block are placed at a smooth ...

Two smooth block are placed at a smooth corner as shown in fig. Both the bloks are having mass m. We apply a force F on the block m. Block A presses block B in the normal direction, due to which pressing force on vertical wall will increase, and pressing force on the horizontal wall decreases, as we increases `F(theta = 37^(@)` with horizontal).

As soon as the pressing force on the horizontal wall by block B become zero, it will lose contact with ground. If the value of F further increases, block B will accelerate in the upward direction and simulaneously block A will towards right.
If the acceleration of block A is a rightwards, then the acceleration of block B will be

A

`(3a)/(4)` upwards

B

`(4a)/(3)` upwards

C

`(3a)/(5) ` upwards

D

`(4a)/(5)` upwards

Text Solution

Verified by Experts

The correct Answer is:
A
To keep regular
contact `a sin theta =b cos theta`
`b=a tan theta =(3)/(4)a`
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