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A body of mass 10 kg lies on a rough inc...

A body of mass `10 kg` lies on a rough inclined plane of inclination `theta = sin^(-1) ((3)/(5))` with the horizontal. When the force of `30 N` is applied on the block parallel to and upward the plane, the total force by the plane on the block is nearly along

A

`OA`

B

`OB`

C

`OC`

D

`OD`

Text Solution

Verified by Experts

The correct Answer is:
A
Frictional force along the in upward
direction `=10g sin theta-30=30Nt` ltbr. `N= log cos theta =80Nt`

Direction of `R` is along `OA`
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