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A system is shown in the figure. Block A...

A system is shown in the figure. Block `A` is moving with `1m//s` towards left. Wedge is moving with `1m//s` towards right. Then speed of the block `B` will be `:`

A

`1m//s`

B

`2m//s`

C

`sqrt(3)m//s`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
Velocity of block `A w.r.t.` wedge is `2m//s`

So we have
`vec(V)_(BW)=vec(V)_(W)-vec(V)_(W)rArrvec(V)_(B)=vec(V)_(BW)+vec(V)_(W)`
So,
`V_(B)=sqrt((V_(W))^(2)+(vec(V)_(BW))^(2)+2V_(W)xxV_(BW)(cos 125^(@)))`
`=sqrt(1^(2)+2^(@)+2xx1xx2xx(-1//2))=sqrt(3)m//s`
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