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A small block of mass m is released from...

A small block of mass `m` is released from a fixed smooth wedge in figure. Initial point is marked as `A`. Bottom of wedge is marked as `B` and at a point `C` the block stops because the straight part of floor is rough.

The friction coefficient of the block with the floor is `:`

A

`(h)/(x_(0)`

B

`(x_(0))/(h)`

C

zero

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
Totol work doen by gravity`=` work done against friction ltbr. `mgh=mu mg. x_(0)`
`=mu=(h)/(x_(0))`
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