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A block of mass m starts at rest at heig...

A block of mass m starts at rest at height on a frictionless inclined plane. The block slides down the plane, travels across a rough horizontal surface with coefficient of kinetic friction `mu` and compresses a spring with force constant `k` a distance `x` before momentarilly coming to rest. Then the spring extends and the block travels back across the rough surface, sliding up the plane. The block travels a total distance d on rough horizontal surface. The correct experssion for the maximum height h' that the block reaches on its return is :

A

`mgh'=mgh-mumgd`

B

`mgh'=mgh+mumgd`

C

`mgh'=mgh+mumgd+kx^(2)`

D

`mgh'=mgh-mumgd-kx^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Final `P.E.` of block `=` Initial `P.E.` of block `+` work done by friction
`:. Mgh' =mgh-mu mg d`
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