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A particle of mass m is fixed to one end...

A particle of mass `m` is fixed to one end of a massless spring of spring constant `k` and natural length `l_(0)`. The system is rotated about the other end of the spring with an angular velocity `omega` ub gravity-free space. The final length of spring is

A

`(m omega^(2)l)/(k)`

B

`(m omega^(2)l)/(k-momega^(2))`

C

`(m omega^(2)l)/(k+momega^(2))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B

`kx=m omega ^(2)l+m omega ^(2)l`
`(k-m omega ^(2))x=m omega ^(2)l`
`x=(m omega^(2)l)/(k-m omega ^(2)) Ans. (B)`
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