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Figure shows an irregular wedge of mass ...

Figure shows an irregular wedge of mass `m` placed on a smooth horizontal surface. Part `BC` is rough.
If the coefficient of friction between the block and wedge is `mu`, and the block comes to rest with respect to wedge at a point `E` on the rough surface then `BE` will be

A

`(H)/(mu)`

B

`(H-h)/(mu)`

C

`(h)/(mu)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
By work `-` energy theorem on the system `:`
`-(mu mg )(BE)-mgh=-(1)/(4) m u^(2)`
`=-(1)/(4)m(4gH)rArr BE=(H-h)/(mu)`
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