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A uniform disc of radius R lies in the x...

A uniform disc of radius `R` lies in the `x-y` plane, with its centre at origin. Its moment of inertia about z-axis is equal to its moment of inertia about line `y = x + c`. The value of `c` will be.
.

A

`-(R)/(2)`

B

`+-(R)/(sqrt(2))`

C

`(+R)/(4)`

D

`-R`

Text Solution

Verified by Experts

The correct Answer is:
B

`I_(PQR)=I_(AOB)+M.(ON)^(2)`
`I_(PQR)=(1)/(4)MR^(2)+M.((C)/(sqrt(2)))^(2)`
But `I_(PQR)=(1)/(2)MR^(2)`

`:. C=+-(R)/(sqrt(2))`
Hence `(B)` is correct.
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Knowledge Check

  • A uniform disc of radius R lies in x-y plane with its centre at origin. Its moment of inertia about the axis x=2R and y=0 is equal to the moment of inertia about the axis y=d and z=0, where d is equal to

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