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A uniform circular disc placed on a hori...

A uniform circular disc placed on a horizontal rough surface has initially a velocity `v_(0)` and an angular velocity `omega_(0)` as shown in the figure. The disc comes to rest after moving some distance in the direction of motion. Then `v_(0)//omega_(0)` is `:`

A

`r//2`

B

`r`

C

`3r//2`

D

2

Text Solution

Verified by Experts

The correct Answer is:
A
`mV_(0)R-(mR^(2))/(2).omega_(0)=0`
`(V_(0))/(omega_(0))=(R)/(2)`
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