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A particle moves with a simple harmonic ...

A particle moves with a simple harmonic motion in a straight line, in the first second starting from rest it travels a distance a and in the next second it travels a distance b in the same direction. The amplitude of the motion is

A

`(2a^(2))/(3a-b)`

B

`a-b`

C

`2a-b`

D

`a//b`

Text Solution

Verified by Experts

The correct Answer is:
A
`x=A cos wt (` as it starts from rest at `t=0)`

`A-a=A cos w ……(1)`
`A-(a+b)=A cos 2w ….(2)`
Solving `(1)` and `(2)` for `A` we get `A =(2a^(2))/(3a-b)`
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