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Two particles A and B having equal mass ...

Two particles `A` and `B` having equal mass are interconnected by a light inextensible string that passes over a smooth pulley. One of the amsses is pulled downward by a constant force `'F'` as shown in diagram, then find the acceleration of the centre of mass of the system `(A+B)`.

Text Solution

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`Mg+F-T=Ma`
`T-Mg=Ma`
`F=2Ma`
`a=(F)/(2M)`
`a_(CM)=(m_(1)a_(1)+m_(2)a_(2))/(m_(1)+m_(2))=(Ma+M(-a))/(M+m)=0`
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