Home
Class 11
PHYSICS
A van accelerates uniformly down an incl...

A van accelerates uniformly down an inclined hill going from reast to `30m//s` in `6s`. During the acceleration , a toy of mass `m=0.1kg` hangs by a light string from the van's ceiling . The acceleration is such that string remains perpendicular to the ceiling. `(` Take `g=10m//s^(2))`

The friction force on the van is

A

Zero

B

`mgcos theta`

C

`mg sin theta`

D

`mg tan theta`

Text Solution

Verified by Experts

The correct Answer is:
A
Acceleration of the van `=(30)/(6)=5 m//s^(2)`
`g sin theta =a`
`rArr sin theta =(1)/(2)`
`rArr theta=30^(@)`
Since accelerated the van is `g sin theta `, there is no friction.
Promotional Banner

Similar Questions

Explore conceptually related problems

A van accelerates uniformly down an inclined hill going from reast to 30m//s in 6s . During the acceleration , a toy of mass m=0.1kg hangs by a light string from the van's ceiling . The acceleration is such that string remains perpendicular to the ceiling. ( Take g=10m//s^(2)) The tension n the string is

A van accelerates uniformly down an inclined hill going from reast to 30m//s in 6s . During the acceleration , a toy of mass m=0.1kg hangs by a light string from the van's ceiling . The acceleration is such that string remains perpendicular to the ceiling. ( Take g=10m//s^(2)) The angle theta of the incline is :

A uniform rope of mass M=0.1kg and length L=10m hangs from the celling. [g=10m//s^(2)] :-

A block of mass 6 kg is kept on rough surface as shown in figure. Find acceleration and friction force acting on the block. (Take g=10m//s^(2) )

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2m//s^(2) . Kinetic friction force acting on block is (take g=10m//s^(2) )

The elevator is going up with an acceleration of g//10 the pulley and the string are light and the pulley is smooth. If reading of spring balance shown is 0.8x Calculate x. (Take g=10m//s^(2))

In the system shown in the adjoining figure, the acceleration of the 1 kg mass is m//s^(2) . (take g = 10 m//s^(2) )

Find the acceleration of masses m_(1) and m_(2) moving down the smooth incline plane. The string and the pulley are masseless and frictionless.

If coeffiecient of friction between the block of mass 2kg and table is 0.4 then out acceleration of the system and tension in the string. (g=10m//s^(2))