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A rope, under tension of 200N and fixed ...

A rope, under tension of `200N` and fixed at both ends, oscialltes in a second harmonic standing wave pattern. The displacement of the rope is given by `y=(0.10)sin ((pix)/(3)) sin (12 pit)`, where `x=0` at one end of the rope, `x` is in metres and `t` is in seconds. Find the length of the rope in metres.

Text Solution

Verified by Experts

`y=0.10sin ((pix)/(3))sin (12 pit)`
`[M. Bank_(-)S.W._(-)4.60]`
`k=(pi)/(3)`
`rArr lambda=6m`
Length of the rope `=lambda=6m`.
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