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If vecA=3hati-4hatj and hatB=-hati-4hatj...

If `vecA=3hati-4hatj` and `hatB=-hati-4hatj`, calculate the direction of `vecA+vecB`

A

`tan^(-1)(4)` with positive X-axis in close wise

B

`tan^(-1)(4)` with X-axis in clock wise

C

`tan^(-1)(4)` with positive X-axis in anticlock wise

D

`tan^(-1)(4)` with negative X-axis in anticlock wise

Text Solution

Verified by Experts

The correct Answer is:
A
`vecR=vecA+vecB,vecR=R_(x)hati+R_(y)hatj , Tan alpha=(R_(y))/(R_(x))`
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Knowledge Check

  • If vecA=3hati-4hatj and vecB=-hati-4hatj , calculate the direction of vecA-vecB .

    A
    along positive x-axis
    B
    along negative x-axis
    C
    along positive y-axis
    D
    along negative y-axis

  • If vecA=4hati-3hatj and vecB=6hati+8hatj then magnitude and direction of vecA+vecB will be

    A
    `5, tan^(-1)(3//4)`
    B
    `5sqrt(5),tan^(-1)(1//2)`
    C
    `10,tan^(-1)(5)`
    D
    `25, tan^(-1)(3//4)`

  • If vecA=2hati+3hatj-hatk and vecB=-hati+3hatj+4hatk then projection of vecA on vecB will be

    A
    `3/(sqrt(13))`
    B
    `3/(sqrt(26))`
    C
    `sqrt(3/26)`
    D
    `sqrt(3/13)`

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