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If vec2hati+3hatj and vecB=2hatj+3hatk t...

If `vec2hati+3hatj` and `vecB=2hatj+3hatk` the component of `vecB` along `vecA` is

A

6

B

`(1)/(6)`

C

`(6)/(13)`

D

`(6)/sqrt(13)`

Text Solution

Verified by Experts

The correct Answer is:
D
`b cos theta=(veca.vecb)/(a)`
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