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The direction consines of a vector vecA ...

The direction consines of a vector `vecA` are `cos alpha=(4)/(5sqrt(2)), cos beta=(1)/sqrt(2)` and `cos gamma=(3)/(5sqrt(2))` then the vector `vecA` is

A

`4hati+hatj+3hatk`

B

`4hati+5hatj+3hatk`

C

`4hati-5hatj-3hatk`

D

`hati+5hatj-hatk`

Text Solution

Verified by Experts

The correct Answer is:
B
`vecA=A_(x)hati+A_(y)hatj+A_(z)hatk`
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