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If vecA=5hati-2hatj+3hatk and vecB=2hati...

If `vecA=5hati-2hatj+3hatk` and `vecB=2hati+hatj+2hatk`, component of `vecB` along `vecA` is

A

`sqrt(14)/(38)`

B

`(28)/sqrt(38)`

C

`sqrt(28)/(38)`

D

`(14)/sqrt(38)`

Text Solution

Verified by Experts

The correct Answer is:
D
`b cos theta=(Veca.vecb)/(a)`
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