[" 29.If "tan(alpha-beta)=(sin2 beta)/(2-cos2 beta)" ,then "],[[" (A) "tan alpha=2tan beta," (B) "tan beta=2tan alphaquad " (C) "2tan]]

If tan (alpha-beta)=(sin 2beta)/(3-cos 2beta) , then

If tan (alpha-beta)=(sin 2beta)/(3-cos 2beta) , then

If tan(alpha-beta)=(sin 2beta)/(3-cos2beta) , then

If tan(alpha-beta)=(sin2 beta)/(3-cos2 beta) then (a) tan alpha=2tan beta(b)tan beta=2tan alpha(c)2tan alpha=3tan beta(d)3tan alpha=2tan beta

If tan (alpha- beta)= (sin 2 beta)/(5-cos 2 beta) , find tan alpha: tan beta .

If tan ( alpha-beta) = (sin 2 beta)/(5-cos 2 beta),"find the value of " tan alpha : tan beta.

If tan(alpha-beta)=(sin2 beta)/(3-cos2 beta), then ( i )tan(alpha)=2tan(beta)( ii) (1)/(2)tan(alpha)=tan(beta)( (ii) 2tan(alpha)=3tan(beta)( iv) 3tan(alpha)=2tan(beta)

If tan alpha=(1-cos beta)/(sin beta), then a )tan3 alpha=tan2 beta(b)tan2 alpha=tan beta(c)tan2 beta=tan alpha(d) none of these

If sin (alpha + beta)=1, sin (alpha- beta)= (1)/(2) , then tan (alpha + 2beta) tan (2alpha + beta) =

If sin (alpha+beta ) =1 , sin (alpha-beta ) =1//2 " then " tan (alpha +2beta ) tan(2alpha+beta ) =