`2^(0.2)xx64xx8^(1.3)xx4^(0.2)=8^(?)`

2^(0)xx4^(0)=8^(0)

8^(0.4)xx4^(1.6)xx2^(1.6)=?48b.64c.52d.76e. none of these

Evaluate : 1. 7^(0)xx4^(0)xx8^(0) 2. (9^(0)+7^(0))xx3^(0)

State true or false. a. 10xx10^(8)=100^(8) b. 3^(0)+8^(0)-7^(0)=4 c. 2^(4)xx4^(2)=8^(6) d. 11^(0)+5^(0)-3^(3)=13

Simplify (8^(3a)xx2^(5)xx2^(2a))/(4xx2^(11a)xx2^(-2a))

Simplify : (8^(3a)xx2^(5)xx2^(2a))/(4xx2^(11a)xx2^(-2a))

((0.000008)^(-2/3)xx(0.0081)^(3/4)xx10^(-2))/((0.0256)^(-1/2)xx(0.125)^(1/3)xx(0.3)^(2))

evaluate 1) 5^2 xx 8^2 2) 2.5^2 xx 4^2 3) (1.5)^2 xx(0.2)^2

((225)^(0.2)xx(225)^(0.3))/((225)^(0.8)xx(225)^(0.2)) is equal to :