Calculate the entropy change for a reaction:
`XrarrY`
Given that `DeltaH^(Theta) = 28.40 kJ mol^(-1)` and equilibrium constant is `1.8 xx 10^(-7) at 298K`.

Calculate the standard entropy change for a reaction X harr Y , If the value of DeltaH^(@) = 28.40 kJ and equilibrium constant is 1.8 xx 10^(-7) at 298 K.

Calculate the standard entropy change for a reaction X rarr Y if the value of DeltaH^@ = +28.40 kJ and equilibrium constant is 1.8 xx 10-7 at 298 K.

Calculate the standard entropy change for the reaction X hArr Y if the value of DeltaH^@ = 28.40 kJ and equilibirum constant is 1.8 xx 10^(-7) at 298 K.

Calculate the standard free energy for a reaction X hArr Y , if the value of equilibrium constant is 1.8 xx 10^(-7) at 298 K.

Calculate the rate constant of a reaction at 293 K when energy of activation is 103 kJ "mol"^(-1) and the rate constant at 273 K is 7.87xx10^(-7)s^(-1) (R=8.314xx10^(-3)kJ"mol"^(-1)KJ^(-1))

Calculate the magnitude of standard entropy change for reaction X hArr Y if DeltaH^(@) = 25 KJ and K_("eq") "is" 10^(-7) at 300 K.

Calculate the magnitude of standard entropy change for reaction X hArr Y if DeltaH^(@) = 25 KJ and K_("eq") "is" 10^(-7) at 300 K.

The value of log_(10)K for a reaction A hArr B is (Given: Delta_(f)H_(298K)^(Theta) =- 54.07 kJ mol^(-1) , Delta_(r)S_(298K)^(Theta) =10 JK^(=1) mol^(-1) , and R = 8.314 J K^(-1) mol^(-1)