[(1)/(4)a-(1)/(2)b+1]^(2)

The domain of definition of the function f(x)=sqrt(sin^(-1)(2x)+(pi)/(6)) for real-valued x is [-(1)/(4),(1)/(2)](b)[-(1)/(2),(1)/(2)](c)(-(1)/(2),(1)/(9))(d)[-(1)/(4),(1)/(4)]

If A=[(1,3),(2,4)] and (AB)^(-1)=[((-1)/(2),(1)/(2)),((1)/(4),0)] , then B^(-1). A^(-1)=

If A=[(1,3),(2,4)] and (AB)^(-1)=[((-1)/(2),(1)/(2)),((1)/(4),0)] , then B^(-1). A^(-1)=

Expand the following using suitable Identities : [1/4a-1/2b+1]^2 .

Write the following in expanded form: (i) (1/4a-1/2b+1)^2 (ii) (-2x+5y-3z)^2

(7)/(2^((1)/(2))+2^((1)/(4))+1)=A+B*2^((1)/(4))+C.2^((1)/(2))+D.2^((3)/(4))

The factors of 8a^(3)+b^(3)-6ab+1 are (a) (2a+b-1)(4a^(2)+b^(2)+1-3ab-2a) (b) (2a-b+1)(4a^(2)+b^(2)-4ab+1-2a+b)(2a+b+1)(4a^(2)+b^(2)+1-2ab-b-2a) (d) (2a-1+b)(4a^(2)+1-4a-b-2ab)

If ((a^(2)+1)^(2))/(2a-i)=x=iy, then x^(2)+y^(2) is equal to ((a^(2)+1)^(4))/(4a^(2)+1) b.((a+1)^(2))/(4a^(2)+1) c.((a^(2)-1)^(2))/((4a^(2)-1)^(2)) d.none of these

If ((a^2+1)^2)/(2a-i)=x+i y , then x^2+y^2 is equal to a. ((a^2+1)^4)/(4a^2+1) b. ((a+1)^2)/(4a^2+1) c. ((a^2-1)^2)/((4a^2-1)^2) d. none of these

|(1,a^(2),a^(4)),(1,b^(2),b^(4)),(1,c^(2),c^(4))|=(a+b)(b+c)(c+a)|(1,1,1),(a,b,c),(a^(2),b^(2),c^(2))|