[f(x)=(1-sin2x+cos xx)/(2cos2x)],[f(16^(-))*f(2y^(-1))]

If f(x)=(1-sin2x+cos2x)/(2cos2x), then the value of f(16^(0))*f(29^(0)) is (1)/(2)(1)/(4)1(3)/(4)

If f(x)=(1-s in2x+cos2x)/(2cos2x) , then the value of f(16^0)dotf(29^0) is 1/2 1/4 1 3/4

If f'(x)=(sin2x)/(cos^(2)2x)," then "f(x) =

The maximum value of f(x)=|(sin^(2)x,1+cos^(2)x,cos2x),(1+sin^(2)x,cos^(2)x,cos2x),(sin^(2)x,cos^(2)x,sin2x)|,x inR is :

If f(x)=|(1+sin^(2)x,cos^(2)x,4sin2x),(sin^(2)x,1+cos^(2)x,4sin2x),(sin^(2)x,cos^(2)x,1+4sin2x)| then the maximum value of f(x) is

int_( then )^( If )f(x)sin x cos xdx=(1)/(2(b^(2)-a^(2)))log f(x)+C

If f(x)=int(sin2x(cos2x-cos4x))/(cos2x(cos2x+cos4x))dx then the value of f((pi)/(3))-f(0) is

Let (d)/(dx)(f(x))=((sin^(12)x-cos^(12)x)/((sin^(2)x-cos^(2)x)(1-3sin^(2)x cos^(2)x))) be such that f(0)=0 then f((pi)/(2)) equals (k pi)/(16). Find the value of k(k in N)

If f(x)sin x cos xdx=(1)/(2(b^(2)-a^(2)))ln f(x)+c, then f(x) is equal to (1)/(a^(2)sin^(2)x+b^(2)cos^(2)x)(b)(1)/(a^(2)sin^(2)x-b^(2)cos^(2)x+b^(2)cos^(2)x+b^(2)cos^(2)x)(d)(1)/(a^(2)cos^(2)x-b^(2)cos^(2)x)

If f(x)=cos(log x), then f(x^(2))f(y^(2))-(1)/(2)[f((x^(2))/(y^(2)))+f(x^(2)y^(2))] has the value